intégration des remarques des relecteurs

[16dcc.git] / stopping.tex

diff --git a/stopping.tex b/stopping.tex
index 9d7e74f374970e7d835203cef4d985973ec8c53a..bb95663c6ca82fee5c21a017b39f496a76d6165b 100644 (file)
--- a/stopping.tex
+++ b/stopping.tex
@@ -366,7 +366,8 @@ Now using Markov Inequality, one has $\P_X(\tau > t)\leq \frac{E[\tau]}{t}$.
 With $t_n=32N^2+16N\ln (N+1)$, one obtains:  $\P_X(\tau > t_n)\leq \frac{1}{4}$. 
 Therefore, using the definition of $t_{\rm mix}$ and
 Theorem~\ref{thm-sst}, it follows that
 With $t_n=32N^2+16N\ln (N+1)$, one obtains:  $\P_X(\tau > t_n)\leq \frac{1}{4}$. 
 Therefore, using the definition of $t_{\rm mix}$ and
 Theorem~\ref{thm-sst}, it follows that

-$t_{\rm mix}\leq 32N^2+16N\ln (N+1)=O(N^2)$.
+$t_{\rm mix}(\frac{1}{4})\leq 32N^2+16N\ln (N+1)=O(N^2)$ and that 
+

 
 
 Notice that the calculus of the stationary time upper bound is obtained
 
 
 Notice that the calculus of the stationary time upper bound is obtained