This section aims at justifying the lightweight attribute of our approach.
To be more precise, we compare the complexity of our schemes to the
-state of the art steganography, namely HUGO~\cite{DBLP:conf/ih/PevnyFB10}.
+ best available steganographic scheme, namely HUGO~\cite{DBLP:conf/ih/PevnyFB10}.
In what follows, we consider a $n \times n$ square image.
First of all, HUGO starts with computing the second order SPAM Features.
-This steps is in $O(n^2 + 2.343^2)$ due to the calculation
+This steps is in $O(n^2 + 2\times 343^2)$ due to the calculation
of the difference arrays and next of the 686 features (of size 343).
Next for each pixel, the distortion measure is calculated by +1/-1 modifying
its value and computing again the SPAM
features. Pixels are thus selected according to their ability to provide
-an image whose SPAM features are close to the original one.
-The algorithm is thus computing a distance between each computed feature,
-and the original ones
-which is at least in $O(343)$ and an overall distance between these
-metrics which is in $O(686)$. Computing the distance is thus in
+an image whose SPAM features are close to the original ones.
+The algorithm thus computes a distance between each feature
+and the original ones,
+which is at least in $O(343)$, and an overall distance between these
+metrics, which is in $O(686)$. Computing the distance is thus in
$O(2\times 343^2)$ and this modification
is thus in $O(2\times 343^2 \times n^2)$.
-Ranking these results may be achieved with an insertion sort which is in
+Ranking these results may be achieved with an insertion sort, which is in
$2.n^2 \ln(n)$.
-The overall complexity of the pixel selection is thus
-$O(n^2 +2.343^2 + 2\times 343^2 \times n^2 + 2.n^2 \ln(n))$, \textit{i.e}
+The overall complexity of the pixel selection is finally
+$O(n^2 +2.343^2 + 2\times 343^2 \times n^2 + 2.n^2 \ln(n))$, \textit{i.e},
$O(2.n^2(343^2 + \ln(n)))$.
Our edge selection is based on a Canny Filter. When applied on a
-$n \times n$ square image the Noise reduction steps is in $O(5^3 n^2)n$.
+$n \times n$ square image, the noise reduction step is in $O(5^3 n^2)$.
Next, let $T$ be the size of the canny mask.
Computing gradients is in $O(4Tn)$ since derivatives of each direction (vertical or horizontal)
are in $O(2Tn)$.
Finally, thresholding with hysteresis is in $O(n^2)$.
The overall complexity is thus in $O((5^3+4T+1)n^2)$.
To summarize, for the embedding map construction, the complexity of Hugo is
-dramatically higher than our scheme.
+dramatically larger than our scheme.
We are then left to express the complexity of the STC algorithm.
According to~\cite{DBLP:journals/tifs/FillerJF11}, it is
in $O(2^h.n)$ where $h$ is the size of the duplicated
-matrix. Its complexity is thus negligeable compared with the embedding map
+matrix. Its complexity is thus negligible compared with the embedding map
construction.
-Thanks to these complexity result, we claim that STABYLO is lightweight.
-
+Thanks to these complexity results, we claim that STABYLO is lightweight.
