From: Jean-François Couchot Date: Mon, 8 Jul 2013 08:27:19 +0000 (+0200) Subject: raph X-Git-Url: https://bilbo.iut-bm.univ-fcomte.fr/and/gitweb/canny.git/commitdiff_plain/f9ab101f6a209bfd67ee84f3aea5bf5ca2582d9b?ds=sidebyside raph --- diff --git a/experiments.tex b/experiments.tex index 2fc8a68..aa8a3e9 100644 --- a/experiments.tex +++ b/experiments.tex @@ -50,7 +50,7 @@ If $b$ is 6, these values are respectively equal to \hline Schemes & \multicolumn{4}{|c|}{STABYLO} & \multicolumn{2}{|c|}{HUGO}& \multicolumn{2}{|c|}{EAISLSBMR} \\ \hline -Embedding & Fixed & \multicolumn{3}{|c|}{Adaptive} & \multicolumn{2}{|c|}{Fixed}& \multicolumn{2}{|c|}{Fixed} \\ +Embedding & Fixed & \multicolumn{3}{|c|}{Adaptive (about 6.35\%)} & \multicolumn{2}{|c|}{Fixed}& \multicolumn{2}{|c|}{Fixed} \\ \hline Rate & 10\% & + sample & +STC(7) & +STC(6) & 10\%&6.35\%& 10\%&6.35\%\\ \hline @@ -88,8 +88,8 @@ into the edge detection. Let us focus on the quality of HUGO images: with a given fixed embedding rate (10\%), HUGO always produces images whose quality is higher than the STABYLO's one. -However our approach always outperforms EAISLSBMR since this one may modify -the two least significant bits whereas STABYLO only alter LSB. +However our approach is always better than EAISLSBMR since this one may modify +the two least significant bits. If we combine \emph{adaptive} and \emph{STC} strategies (which leads to an average embedding rate equal to 6.35\%) @@ -141,7 +141,7 @@ can be favorably executed thanks to an ensemble classifier. \hline Schemes & \multicolumn{4}{|c|}{STABYLO} & \multicolumn{2}{|c|}{HUGO}& \multicolumn{2}{|c|}{EAISLSBMR}\\ \hline -Embedding & Fixed & \multicolumn{3}{|c|}{Adaptive} & \multicolumn{2}{|c|}{Fixed}& \multicolumn{2}{|c|}{Fixed} \\ +Embedding & Fixed & \multicolumn{3}{|c|}{Adaptive (about 6.35\%)} & \multicolumn{2}{|c|}{Fixed}& \multicolumn{2}{|c|}{Fixed} \\ \hline Rate & 10\% & + sample & +STC(7) & +STC(6) & 10\%& 6.35\%& 10\%& 6.35\%\\ \hline diff --git a/main.tex b/main.tex index c4bb7fc..002666a 100755 --- a/main.tex +++ b/main.tex @@ -154,6 +154,7 @@ examined for the sake of completeness. Finally, the systematic replacement of all the LSBs of edges by binary digits provided by the BBS generator will be investigated, and the consequences of such a replacement, in terms of security, will be discussed. +Furthermore, we plan to investigate information hiding on other models, high frequency for JPEG encoding for instance. \bibliographystyle{plain} diff --git a/ourapproach.tex b/ourapproach.tex index 9cf0384..9cce7a2 100644 --- a/ourapproach.tex +++ b/ourapproach.tex @@ -3,7 +3,7 @@ four main steps: the data encryption (Sect.~\ref{sub:bbs}), the cover pixel selection (Sect.~\ref{sub:edge}), the adaptive payload considerations (Sect.~\ref{sub:adaptive}), and how the distortion has been minimized (Sect.~\ref{sub:stc}). -The message extraction is finally presented (Sect.\ref{sub:extract}) and a running example ends this section (Sect.~\ref{sub:xpl}). +The message extraction is finally presented (Sect.~\ref{sub:extract}) and a running example ends this section (Sect.~\ref{sub:xpl}). The flowcharts given in Fig.~\ref{fig:sch} @@ -99,7 +99,7 @@ As the Canny algorithm is well known and studied, fast, and implementable on many kinds of architectures like FPGAs, smartphones, desktop machines, and GPUs, we have chosen this edge detector for illustrative purpose. -\JFC{il faudrait comparer les complexites des algo fuzy and canny} +%\JFC{il faudrait comparer les complexites des algo fuzy and canny} This edge detection is applied on a filtered version of the image given @@ -133,7 +133,7 @@ depending on the embedding rate that is either \emph{adaptive} or \emph{fixed}. In the former the embedding rate depends on the number of edge pixels. The higher it is, the larger the message length that can be inserted is. Practically, a set of edge pixels is computed according to the -Canny algorithm with an high threshold. +Canny algorithm with a high threshold. The message length is thus defined to be less than half of this set cardinality. If $x$ is then too short for $m$, the message is split into sufficient parts