From: Raphael Couturier Date: Wed, 20 Apr 2011 13:52:09 +0000 (+0200) Subject: suite description algo bertsekas X-Git-Url: https://bilbo.iut-bm.univ-fcomte.fr/and/gitweb/loba-papers.git/commitdiff_plain/11a214bdac1c00f5f5f8ed9ff672afdb27a23b7d suite description algo bertsekas --- diff --git a/supercomp11/supercomp11.tex b/supercomp11/supercomp11.tex index 6a48cd3..0479906 100644 --- a/supercomp11/supercomp11.tex +++ b/supercomp11/supercomp11.tex @@ -1,3 +1,4 @@ + \documentclass[smallextended]{svjour3} \usepackage[utf8]{inputenc} \usepackage[T1]{fontenc} @@ -143,7 +144,35 @@ amount of load received by processor $j$ from processor $i$ at time $t$. Then the amount of load of processor $i$ at time $t+1$ is given by: \begin{equation} x_i(t+1)=x_i(t)-\sum_{j\in V(i)} s_{ij}(t) + \sum_{j\in V(i)} r_{ji}(t) +\label{eq:ping-pong} +\end{equation} + + +Some conditions are required to ensure the convergence. One of them can be +called the \texttt{ping-pong} condition which specifies that: +\begin{equation} +x_i(t)-\sum _{k\in V(i)} s_{ik}(t) \geq x_j^i(t)+s_{ij}(t) \end{equation} +for any processor $i$ and any $j \in V(i)$ such that $x_i(t)>x_j^i(t)$. This +condition aims at avoiding a processor to send a part of its load and beeing +less loaded after that. + +Nevertheless, we think that this condition may lead to deadlocks in some +cases. For example, if we consider only three processors and that processor $1$ +is linked to processor $2$ which is also linked to processor $3$ (i.e. a simple +chain wich 3 processors). Now consider we have the following values at time $t$: +\begin{eqnarray*} +x_1(t)=10 \\ +x_2(t)=100 \\ +x_3(t)=99.99\\ + x_3^2(t)=99.99\\ +\end{eqnarray*} +In this case, processor $2$ can either sends load to processor $1$ or processor +$3$. If it sends load to processor $1$ it will not satisfy condition +(\ref{eq:ping-pong}) because after the sending it will be less loaded that +$x_3^2(t)$. So we consider that the \texttt{ping-pong} condition is probably to +strong. Currently, we did not try to make another convergence proof without this +condition or with a weaker condition. \section{Best effort strategy}