-If host `A` sends ``100kB`` (a hundred kilobytes) to host `B`, one can expect that this communication would take `0.81`
-seconds to complete according to a simple latency-plus-size-divided-by-bandwidth model (0.01 + 8e5/1e6 = 0.81) since the
-latency is small enough to ensure that the physical bandwidth is used (see the discussion on CM02 above). However, the
-LV08 model is more complex to account for three phenomena that directly impact the simulation time:
+If host `A` sends ``100kB`` (a hundred kilobytes, that is, 8e5 bits) to host `B`, one can expect that this communication would
+take `0.81` seconds to complete according to a simple latency-plus-size-divided-by-bandwidth model (0.01 + 8e5/1e6 = 0.81 -- the
+size was converted from bytes to bits) since the latency is small enough to ensure that the physical bandwidth is used (see the
+discussion on CM02 above). However, the LV08 model is more complex to account for three phenomena that directly impact the
+simulation time: