7 """Convertit un nombre en binaire"""
9 res =[0 for i in range(n)]
24 acc = acc + 2**(n-i-1)
28 def MarkovMatrixUnPas(fbin,n,p2n,lp2nm1):
29 MM = np.zeros(p2n*p2n).reshape((p2n,p2n))
34 image = fbin[tuple(ib)]
38 MM[i, dec(ipb,n)] +=float(1)/(2*n)
42 def MarkovMatrixUnPas(fbin,n,p2n,lp2nm1):
43 MM = np.zeros(p2n*p2n).reshape((p2n,p2n))
48 image = fbin[tuple(ib)]
52 MM[i, dec(ipb,n)] +=float(1)/(n)
59 def MarkovMatrixSaut(fbin,n,p2n,lp2nm1):
60 MM = np.zeros(p2n*p2n).reshape((p2n,p2n))
65 image = fbin[tuple(ib)]
72 MM[i, dec(ipb,n)] +=float(1)/(2*2**n)
76 def MarkovMatrixSaut(fbin,n,p2n,lp2nm1):
77 MM = np.zeros(p2n*p2n).reshape((p2n,p2n))
82 image = fbin[tuple(ib)]
89 MM[i, dec(ipb,n)] +=float(1)/(2**n)
96 # f is the binary function
97 # b is the number to iterate
98 # x0 is the intial binary conf
100 #print "************************"
103 if rn.randint(0,1) == 1:
105 st = rn.randint(0,n-1)
106 #print "x["+str(st)+"]="+str(xp[st])+"->"+str(image[st])
113 ## n'est pas un circuit hmiltonien
115 #lf +=[ [13, 10, 9, 14, 3, 11, 1, 12, 15, 4, 7, 5, 2, 6, 0, 8]] #4
116 #lf += [[29, 22, 25, 30, 19, 27, 24, 16, 21, 6, 5, 28, 23, 26, 1, 17, 31, 12, 15, 8, 10, 14, 13, 9, 3, 2, 7, 20, 11, 18, 0, 4],[29, 22, 21, 30, 19, 27, 24, 28, 7, 20, 5, 4, 23, 26, 25, 17, 31, 12, 15, 8, 10, 14, 13, 9, 3, 2, 1, 6, 11, 18, 0,16]] # essai des 2 elements à 5
124 #f += [[29, 22, 25, 30, 19, 27, 24, 16, 21, 6, 5, 28, 23, 26, 1, 17, 31, 12, 15, 8, 10, 14, 13, 9, 3, 2, 7, 20, 11, 18, 0, 4]] #5
125 lf += [[55, 60, 45, 44, 58, 62, 61, 48, 53, 50, 52, 36, 59, 34, 33, 49, 15, 42, 47, 46, 35, 10, 57, 56, 7, 54, 39, 37, 51, 2, 1, 40, 63, 26, 25, 30, 19, 27, 17, 28, 31, 20, 23, 21, 18, 22, 16, 24, 13, 12, 29, 8, 43, 14, 41, 0, 5, 38, 4, 6, 11, 3, 9, 32]] #6
128 lf += [[111, 94, 93, 116, 122, 90, 125, 88, 115, 126, 119, 84, 123, 98, 81, 120, 109, 106, 105, 110, 99, 107, 104, 72, 71, 118, 117, 96, 103, 102, 113, 64, 79, 86, 95, 124, 83, 91, 121, 24, 85, 22, 69, 20, 19, 114, 17, 112, 77, 76, 13, 108, 74, 10, 9, 73, 67, 66, 101, 100, 75, 82, 97, 0, 127, 54, 57, 62, 51, 59, 56, 48, 53, 38, 37, 60, 55, 58, 33, 49, 63, 44, 47, 40, 42, 46, 45, 41, 35, 34, 39, 52, 43, 50, 32, 36, 29, 28, 61, 92, 26, 18, 89, 25, 87, 30, 23, 4, 27, 2, 16, 80, 31, 78, 15, 14, 3, 11, 8, 12, 5, 70, 21, 68, 7, 6, 65, 1]] #7
129 lf += [[223, 190, 249, 254, 187, 251, 233, 232, 183, 230, 247, 180, 227, 178, 240, 248, 237, 236, 253, 172, 203, 170, 201, 168, 229, 166, 165, 244, 163, 242, 241, 192, 215, 220, 205, 216, 218, 222, 221, 208, 213, 210, 212, 214, 219, 211, 217, 209, 239, 202, 207, 140, 139, 234, 193, 204, 135, 196, 199, 132, 194, 130, 225, 200, 159, 62, 185, 252, 59, 250, 169, 56, 191, 246, 245, 52, 243, 50, 176, 48, 173, 238, 189, 44, 235, 42, 137, 184, 231, 38, 37, 228, 35, 226, 177, 224, 151, 156, 141, 152, 154, 158, 157, 144, 149, 146, 148, 150, 155, 147, 153, 145, 175, 206, 143, 136, 11, 142, 129, 8, 7, 198, 197, 4, 195, 2, 161, 160, 255, 124, 109, 108, 122, 126, 125, 112, 117, 114, 116, 100, 123, 98, 97, 113, 79, 106, 111, 110, 99, 74, 121, 120, 71, 118, 103, 101, 115, 66, 65, 104, 127, 90, 89, 94, 83, 91, 81, 92, 95, 84, 87, 85, 82, 86, 80, 88, 77, 76, 93, 72, 107, 78, 105, 64, 69, 102, 68, 70, 75, 67, 73, 96, 55, 58, 45, 188, 51, 186, 61, 40, 119, 182, 181, 53, 179, 54, 33, 49, 15, 174, 47, 60, 171, 46, 57, 32, 167, 6, 36, 164, 43, 162, 1, 0, 63, 26, 25, 30, 19, 27, 17, 28, 31, 20, 23, 21, 18, 22, 16, 24, 13, 10, 29, 14, 3, 138, 41, 12, 39, 134, 133, 5, 131, 34, 9, 128]]#8
133 # 14 = (1,1,1,0) = f(0,0,0,0)
134 # 6 = (0,1,1,0) = f(0,0,0,1)
136 # 8 = (1,0,0,0) = f(1,1,1,1)
140 n = int(log(len(f))/log(2))
144 # pour eviter de le calculer a chaque fois
145 # fbin est la fonction (representee comme un dico)
146 # qui au tuple binaire (x3,x2,x1,x0) associe
147 # le nombre f(x3,x2,x1,x0)
149 for j in range(len(f)):
150 fbin[tuple(bin(j,n))] = bin(f[j],n)
152 MM = MarkovMatrixUnPas(fbin,n,p2n,lp2nm1)
153 M = np.zeros(p2n*p2n).reshape((p2n,p2n))
156 MMs = MarkovMatrixSaut(fbin,n,p2n,lp2nm1)
157 Ms = np.zeros(p2n*p2n).reshape((p2n,p2n))
166 error =max([sqrt(sum([(M[i,j] - float(1)/p2n)**2 for i in range(p2n)])) for j in range(p2n)])
177 error =max([sqrt(sum([(Ms[i,j] - float(1)/p2n)**2 for i in range(p2n)])) for j in range(p2n)])
183 return n, cpt-1, cpts-1
189 n,cpt1,cpt2 = traite_f(f)
191 print 8*n*n + 4*n*log(n+1)#,8*n*n + (n+2)*(log(n)+2)
192 print "Pour "+str(n)+" bits et pour eps="+str(dev)+", appels a rand moy pr 1 bit genere.",
193 print "En marchant:", cpt1*log(n)/(log(2)*n),
194 print "En sautant:", cpt2