-Checking if a graph is strongly connected is not difficult. For
-example, consider the function $f_1\left(x_1,\dots,x_n\right)=\left(
-\overline{x_1},x_1,x_2,\dots,x_{n-1}\right)$. As $\Gamma(f_1)$ is
-obviously strongly connected, then $G_{f_1}$ is a chaotic map.
+Checking if a graph is strongly connected is not difficult
+(by the Tarjan's algorithm for instance).
+Let be given a strategy $S$ and a function $f$ such that
+$\Gamma(f)$ is strongly connected.
+In that case, iterations of the function $G_f$ as defined in
+Eq.~(\ref{eq:Gf}) are chaotic according to Devaney.
+
+
+Let us then consider two function $f_0$ and $f_1$ both in
+$\Bool^n\to\Bool^n$ defined as follows that are used all along this article.
+The former is the vectorial negation, \textit{i.e.},
+$f_{0}(x_{1},\dots,x_{n}) =(\overline{x_{1}},\dots,\overline{x_{n}})$.
+The latter is $f_1\left(x_1,\dots,x_n\right)=\left(
+\overline{x_1},x_1,x_2,\dots,x_{n-1}\right)$.
+It is not hard to see that $\Gamma(f_0)$ and $\Gamma(f_1)$ are
+both strongly connected, then iterations of $G_{f_0}$ and of
+$G_{f_1}$ are chaotic according to Devaney.